3(x^2+7)=(3x^2+21)=

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Solution for 3(x^2+7)=(3x^2+21)= equation: 



3(x^2+7)=(3x^2+21)=

We move all terms to the left:

3(x^2+7)-((3x^2+21))=0

We multiply parentheses

3x^2-((3x^2+21))+21=0



We calculate terms in parentheses: -((3x^2+21)), so:

(3x^2+21)

We get rid of parentheses

3x^2+21

Back to the equation:

-(3x^2+21)



We get rid of parentheses

3x^2-3x^2-21+21=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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